# How to Calculate distance between two points in php by passing latitude and longitude

In this quick tutorial I am going to share a quick php function to Calculate distance between two points in php using latitude and longitude,This below function calculates the distance between two points.
Passed to function:
lat1, lon1 = Latitude and Longitude of point 1 (in decimal degrees)
lat2, lon2 = Latitude and Longitude of point 2 (in decimal degrees)

Here is the function.

```function calDistance(\$lat1, \$lon1, \$lat2, \$lon2) { \$theta = \$lon1 - \$lon2; \$miles = (sin(deg2rad(\$lat1)) * sin(deg2rad(\$lat2))) + (cos(deg2rad(\$lat1)) * cos(deg2rad(\$lat2)) * cos(deg2rad(\$theta))); \$miles = acos(\$miles); \$miles = rad2deg(\$miles); \$result['miles'] = \$miles * 60 * 1.1515; \$result['feet'] = \$result['miles'] * 5280; \$result['yards'] = \$result['feet'] / 3; \$result['kilometers'] = \$result['miles'] * 1.609344; \$result['meters'] = \$result['kilometers'] * 1000; return \$result; }```

Example.

```\$distance = calDistance(\$lat1='28.7041', \$lon1='77.1025', \$lat2='26.5041', \$lon1='75.0025' ); var_dump(\$distance); /* OUTPUT: array(5) { ["miles"]=> float(199.07401385446) ["feet"]=> float(1051110.7931515) ["yards"]=> float(350370.26438384) ["kilometers"]=> float(320.37856975259) ["meters"]=> float(320378.56975259) } */```

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Posted in: PHP

## 2 Replies to “How to Calculate distance between two points in php by passing latitude and longitude”

1. Calaf says:

In this function you mention the variables \$kilometers and \$feet but neither are anywhere to be found.
Can you explain it to me, please?
Thank you.

2. Rohit Kumar says:

This was mistake, Now fixed

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